Inclined Plane Annotated Scaled Drawing
Engagement:eight/27/14 Intro:In this activity nosotros tested a simple motorcar on our vex kit simple machine.We then had to calculate everything from that.We presented in class to anybody.Nosotros also had to accept notes when other presented. Office 1 – Lever, Bicycle and Axle, and Pulley Offset Class Lever Create a scaled annotated drawing of the first grade lever. Calculate the platonic mechanical advantage of the lever organization. Formula Substitute / Solve Terminal Answer IMA=De/Dr IMA= Calculate the ideal attempt strength needed to overcome the known resistance force. Formula Substitute / Solve Last Answer Fe=Fr x Dr/De Fr=one*vi/6.25 Fe=0.96lbs Summate the bodily mechanical advantage of the lever organisation. Formula Substitute / Solve Last Answer AMA=Fr/Fe AMA=1/0.96 AMA=ane.04 Calculate the efficiency of the lever organisation. Formula Substitute / Solve Last Respond eff=(AMA/IMA) * 100 1.04/1.04 eff=100% List and depict two examples of a outset form lever. see saw or crowbar Calculate the platonic mechanical reward of the lever system. Formula Substitute / Solve Final Answer IMA=De/Dr IMA= 6/iii.5 one.71 Calculate the platonic endeavour forcefulness needed to overcome the known resistance force. Formula Substitute / Solve Final Respond Fe*De=Fr*Dr Fe*5.v=3*ane.07 Fe=.58 lbs Calculate the actual mechanical advantage of the lever arrangement. Formula Substitute / Solve Final Answer AMA=Fr/Iron 1.07/.5 2.fourteen Calculate the efficiency of the lever organisation. Formula Substitute / Solve Last Respond AMA/IMA 2.14/one.71 125% List and depict ii examples of a second form lever. A wheelbarrow and a hammer Third Form Lever Create a scaled annotated drawing of the third class lever. Calculate the ideal mechanical advantage of the lever organization. Formula Substitute / Solve Final Reply De/Dr 6/12 IMA=.5 Calculate the ideal effort force needed to overcome the known resistance force. Formula Substitute / Solve Final Reply Atomic number 26*De=Fr*Dr 1.07*sixteen=half-dozen*Fe 12.84=6Fe 12.84/half-dozen Fe=2.14 Calculate the actual mechanical advantage of the lever system. Formula Substitute / Solve Concluding Answer Fr/Fe 1.07/2.14 AMA=0.5 Summate the efficiency of the lever system. Formula Substitute / Solve Concluding Answer AMA/IMA 0.v/0.5 *100 eff=100% Listing and describe two examples of a 3rd class lever. Tweezers and scissors Is it possible for a beginning or second class lever to take a mechanical reward less than one, or for a 3rd class lever to have a mechanical advantage greater than one? Justify your answer. When y'all were solving for mechanical advantage, what units did the last answer require? Explain why. Inches because Bike and Axle What is the diameter of the wheel ? 4.375 in What is the diameter of the axle ? 2.75 in Attach the resistance weight to the string attached to the axle. Use your fingers to turn the wheel. Based on where the applied effort and resistance are located, identify the altitude traveled by both forces during i full rotation. D East =2x 3.14 x2 .1875=13.7 in D R = 2x 3.14x 1.375=8.64 Remove the resistance weight from the axle string and attach the weight to the wheel. Use your fingers to plough the axle. Based on where the applied try and resistance are located, identify the distance traveled past both forces during ane full rotation. D E =8.64in D R = 13.7 in Wrap the resistance weight effectually the axle using string. Use the force sensor fastened to the string wrapped around the wheel to create equilibrium. Based on where the applied attempt and resistance are located, identify the force required to concur the system in equilibrium. F Due east =.726 lb F R = 1.07 lb Wrap the weight around the wheel using string. Use the strength sensor attached to string on the axle to create equilibrium. Based on where the applied endeavour and resistance are located, place the forcefulness required to hold the arrangement in equilibrium. F Due east =1.716 lb F R = i.07 lb For the same resistance, is the effort forcefulness larger when the effort is applied to the wheel or when it is applied to the axle ? Explicate why. The effort force is larger when the effort is practical to the axle. because the altitude is smaller on the axle. Create a scaled annotated drawing of the bike and axle system. Calculate the platonic mechanical reward of the wheel and beam system if the resistance force is applied to the axle . Formula Substitute / Solve Final Respond IMA=De/Dr 13.⅞.64 one.59 Calculate the platonic mechanical reward of the cycle and beam system if the resistance force is applied to the cycle . Formula Substitute / Solve Final Answer IMA=De/Dr 8.64/13.seven .631 Calculate the platonic try force needed to overcome the known resistance strength if the resistance forcefulness is applied to the wheel . Formula Substitute / Solve Final Answer Fe x De=Fr x Dr 13.7 ten i.07/eight.64 1.69 Calculate the actual mechanical reward of your wheel and axle system if the resistance force is applied to the wheel . Formula Substitute / Solve Final Respond AMA=Fr/Fe 1.07/1.716 .62 Calculate the efficiency of the bike and axle system when the resistance strength is applied to the wheel . Formula Substitute / Solve Final Respond %eff=AMA/IMA .62/.631 98% List and describe two examples of a bike and axle. Wheels n car and running cycle for hamster If you know the dimensions of a wheel and axle organisation used for an machine, how can you lot determine the distance covered for each axle revolution? Explicate whatsoever additional information and necessary formulas. one time you get the bore of the wheel Why is the steering wheel on a school bus so large? Because the distance is to large it is easier to turn the motorcoach Stock-still Pulley Create a scaled annotated drawing of the fixed pulley system. Summate the ideal mechanical advantage of the fixed pulley system. Formula Substitute / Solve Concluding Answer IMA= # strands IMA=1 IMA=one Summate the actual mechanical advantage of the fixed caster system. Formula Substitute / Solve Final Reply AMA=F_r/F_e AMA=(1lb)/(0.71)= AMA=1.41 Calculate the efficiency of the fixed pulley system. Formula Substitute / Solve Concluding Answer eff=(AMA/IMA) 100 eff=one.28/1=1.28 128% Movable Pulley Create a scaled annotated drawing of the pulley system. Summate the actual mechanical advantage of the pulley organisation. Formula Substitute / Solve Concluding Reply AMA=Fr/Iron .950 Lbs. / .660 Lbs. one.44 Calculate the ideal mechanical advantage of the pulley system. Formula Substitute / Solve Final Answer IMA= De/Dr nine ⅛ / 5 ¾ = 1.59 or i.58695652 Calculate the efficiency of the fixed caster system. Formula Substitute / Solve Concluding Answer AMA/IMA one.44/one.59 0.90566037735 91% Part ii – Inclined Aeroplane and Screw Inclined Airplane Create a scaled annotated drawing of the inclined aeroplane arrangement. Calculate the ideal mechanical advantage of the inclined plane organization. Formula Substitute / Solve Terminal Reply IMA = De/Dr fifteen/xi.75 one.27 Calculate the ideal effort forcefulness needed to overcome the known resistance strength. Formula Substitute / Solve Concluding Reply Fe*De=Fr*Dr Atomic number 26*15=1*xi.75 .78 Calculate the bodily mechanical advantage of the inclined plane system. Formula Substitute / Solve Final Answer AMA = Fr/Fe .85/1 .85 Calculate the efficiency of the inclined plane organization. Formula Substitute / Solve Terminal Reply eff= AMA/IMA .85/1.27 .66=66% List and describe two examples of an inclined plane. Ramp and a Roller Coaster. Fixed Pulley Create a scaled annotated drawing of the stock-still pulley organization. Calculate the ideal mechanical advantage of the fixed pulley system. Formula Substitute / Solve Final Answer IMA = # strands IMA = i IMA = 1 Summate the actual mechanical advantage of the fixed pulley system. Formula Substitute / Solve Final Respond AMA = F_R/F_E AMA = (ane lb)/(0.71 lb) AMA = 1.41 Calculate the efficiency of the fixed pulley organization. Formula Substitute / Solve Final Answer eff = AMA/IMA eff = ane.28 / i = 1.28 128% Block and Tackle IMA = iii Fe = .350 Fr = 1 lb Calculate the actual mechanical advantage of the caster organisation. Formula Substitute / Solve Final Reply AMA = Fr/Fe AMA = i lb / .350 AMA = 2.85 Calculate the ideal mechanical advantage of the pulley system. Formula Substitute / Solve Concluding Answer IMA = # of strands IMA = # of strands = 3 IMA = 3 Calculate the efficiency of the fixed caster system. Formula Substitute / Solve Final Reply Eff=AMA/IMA(100) Eff = 2.85 / three Eff = 95% Describe two examples of a caster system. A. Elevators B. Exercise machines The fixed pulley contained two strands. Explicate the role of each strand. Both strands are used to change direction. The movable caster contained two strands. Explain the role of each strand. The load is distributed over the two strands, one is combined to ceiling and the other is under the weight. In the cake and tackle organisation, explain how mechanical advantage relates to the number of strands. IMA is the number of supporting strands because it is the advantage of having that corporeality of cord. In a block and tackle organisation with a mechanical advantage of 3, the try is measured at xv lbf. The resistance, when counterbalanced, is measured at 42 lbf. What factors might account for the loss in energy? Non parallel strings or the friction from the strings. Spiral Create a scaled annotated cartoon of the screw system. Calculate the platonic mechanical reward of the spiral. Formula Substitute / Solve Last Answer IMA = De/Dr 13.7 / .123 IMA = 111.38 Summate the platonic endeavour force needed to overcome the known resistance forcefulness. Formula Substitute / Solve Final Answer Fe*De = Fr*Dr 13.7 * Fe = .123*1.07 Fe = .01 lbs Summate the actual mechanical advantage of the spiral. Formula Substitute / Solve Final Answer AMA = Fr/Fe 1.07/.65 AMA = one.646 Summate the efficiency of the spiral. Formula Substitute / Solve Last Answer Eff = AMA / IMA 1.646 / 111.38 = .014 Eff = ane.4& Describe 2 examples of a screw. Screwjack and C clench Why do you think overcoming a resistance force using a screw is so easy? The screw is an inclined plane and is being slid up the entire manner. The screw is a combination of two simple machines. Identify and defend what ii elementary machines you believe are combined to create a screw. Inclined airplane and wedge. The threads are slanted and the wedge pushed through the cloth. Role ii – Inclined Plane and Screw Inclined Plane Create a scaled annotated cartoon of the inclined plane system. Calculate the ideal mechanical advantage of the inclined plane system. Formula Substitute / Solve Final Respond IMA = De/Dr 15/eleven.75 1.27 Calculate the platonic effort force needed to overcome the known resistance strength. Formula Substitute / Solve Last Reply Fe*De=Fr*Dr Fe*fifteen=1*eleven.75 .78 Calculate the actual mechanical advantage of the inclined plane system. Formula Substitute / Solve Final Answer AMA = Fr/Fe .85/1 .85 Calculate the efficiency of the inclined plane arrangement. Formula Substitute / Solve Final Answer eff= AMA/IMA .85/1.27 .66=66% List and describe two examples of an inclined airplane. Ramp and a Roller Coaster. Fixed Pulley Create a scaled annotated cartoon of the stock-still pulley system. Calculate the ideal mechanical advantage of the stock-still pulley organisation. Formula Substitute / Solve Concluding Answer IMA = # strands IMA = 1 IMA = 1 Calculate the actual mechanical reward of the fixed caster arrangement. Formula Substitute / Solve Final Reply AMA = F_R/F_E AMA = (i lb)/(0.71 lb) AMA = 1.41 Calculate the efficiency of the fixed caster system. Formula Substitute / Solve Final Reply eff = AMA/IMA eff = one.28 / 1 = 1.28 128% Block and Tackle IMA = 3 Fe = .350 Fr = 1 lb Calculate the bodily mechanical advantage of the caster arrangement. Formula Substitute / Solve Concluding Respond AMA = Fr/Fe AMA = 1 lb / .350 AMA = 2.85 Calculate the ideal mechanical advantage of the pulley system. Formula Substitute / Solve Concluding Reply IMA = # of strands IMA = # of strands = 3 IMA = 3 Calculate the efficiency of the fixed caster organisation. Formula Substitute / Solve Terminal Reply Eff=AMA/IMA(100) Eff = 2.85 / 3 Eff = 95% Describe two examples of a pulley organisation. A. Elevators B. Do machines The fixed pulley contained 2 strands. Explain the function of each strand. Both strands are used to alter management. The movable pulley contained two strands. Explain the role of each strand. The load is distributed over the two strands, one is combined to ceiling and the other is nether the weight. In the block and tackle system, explain how mechanical advantage relates to the number of strands. IMA is the number of supporting strands because it is the advantage of having that amount of string. In a block and tackle organization with a mechanical reward of three, the effort is measured at 15 lbf. The resistance, when balanced, is measured at 42 lbf. What factors might account for the loss in energy? Non parallel strings or the friction from the strings. Spiral Create a scaled annotated drawing of the screw organization. Calculate the ideal mechanical advantage of the spiral. Formula Substitute / Solve Final Answer IMA = De/Dr 13.seven / .123 IMA = 111.38 Calculate the ideal effort force needed to overcome the known resistance force. Formula Substitute / Solve Concluding Answer Fe*De = Fr*Dr 13.7 * Fe = .123*1.07 Fe = .01 lbs Calculate the actual mechanical advantage of the screw. Formula Substitute / Solve Concluding Respond AMA = Fr/Fe ane.07/.65 AMA = one.646 Calculate the efficiency of the screw. Formula Substitute / Solve Final Answer Eff = AMA / IMA 1.646 / 111.38 = .014 Eff = 1.4 Describe two examples of a screw. Screwjack and C clamp Why do you think overcoming a resistance force using a screw is so easy? The screw is an inclined plane and is beingness slid upwardly the entire way. The spiral is a combination of 2 simple machines. Place and defend what two simple machines you believe are combined to create a spiral. Inclined aeroplane and wedge. The threads are slanted and the wedge pushed through the cloth.
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